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HemiRambler

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Joined
Apr 20, 2010
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270
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Cleveland, Ohio
Sure - like anything you've got to stick within the design limits. Circuit rating as well as switch ratings are different. It's not rocket science though - it's as simple as PIE.


EDIT: OK no more teasing ;-0 But be careful listening to me - I'm mechanical not electrical ! Here's what I remember

P (Power aka Watts)
I (Current aka amps)
E (Electricity aka volts)

So... P=I E

or a 40watt fixture = I * 120 volts


40/120 = I

.33=I

or stated 1/3 amp draw by a 40w load on a 120v circuit. So depending on your watts pretty much a LOT of them, probably to the point that you'd want to break them up into a couple different zones if for no other reason than to save some electricity - may not always need FULL LIGHTING.


So electrical types - how'd I do??? :)
I remember hearing that there is a limit to how many florescent lights (8 foot in my case ) you can put on a single switch. Is that true?
 
Last edited:

MrMark

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Jan 25, 2010
Messages
4,626
Location
Southern Cal.
Yes, you need to look at the ballast to get the load amp rating for each light. Add them up. You should not exceed 80 percent of your circuit rating.
 

Charles (in GA)

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Messages
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Location
50 mi south of Atlanta
If you use a 20 amp breaker and 12 gauge wire, just be sure and buy a 20 amp rated switch, not some cheapie. Your circuit is only as good as the lowest common denominator.

As noted, lighting is consider a continuous load and as such you cannot exceed 80% of the circuit's rating, 16 amps on a 20 amp circuit, and 12 amps on a 15 amp circuit. With fluorescent lights, this probably won't happen.

Charles

Charles
 
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MrMark

Well-known member
Joined
Jan 25, 2010
Messages
4,626
Location
Southern Cal.
Sure - like anything you've got to stick within the design limits. Circuit rating as well as switch ratings are different. It's not rocket science though - it's as simple as PIE.


EDIT: OK no more teasing ;-0 But be careful listening to me - I'm mechanical not electrical ! Here's what I remember

P (Power aka Watts)
I (Current aka amps)
E (Electricity aka volts)

So... P=I E

or a 40watt fixture = I * 120 volts


40/120 = I

.33=I

or stated 1/3 amp draw by a 40w load on a 120v circuit. So depending on your watts pretty much a LOT of them, probably to the point that you'd want to break them up into a couple different zones if for no other reason than to save some electricity - may not always need FULL LIGHTING.


So electrical types - how'd I do??? :)

Not bad. Just take out the bold. Or, I suppose if you want to keep the "E" change it to Electromotive force.
 
Last edited:

mrb

Well-known member
Joined
Dec 31, 2008
Messages
3,734
Thanks for the help. I was under the impression there was something special about the balasts.

there is. completely ignore the wattage of the lamps -you have to calculate based on the amps from the nameplate on the ballast.
 
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