will i ever find this saw again

[jwhayden]

late 80's black and decker industrial 71/4 super sawcat 13 amp model 2694. heavy but the best saw i ever owned.dropped from 40some feet bounced twice and all i had to do before i started useing it was straighten the edge of the base. still have it just ordered parts for it but i would like another one.if anyone knows of one let me know. thanks

 

[jakemac]

Keep an eye on ebay. It may take a while.

 

[gus1962]

Ebay or craigslist.

 

[stratman977]

Heres a 2695 8 1/4". Not sure why the seller thinks its worth $250. Is there something special about these?

http://www.ebay.com/itm/A4-Vintage-...aultDomain_0&hash=item58b78f039a#ht_796wt_794

 

[Major Ramifications]

stratman977,
That saw is worth about $2.50, not $250.

 

[dwysywd]

stratman977,

That saw is worth about $2.50, not $250.

LoL. That's great. Only on Fleabay and CL will someone go to that ridiculous a price because they put "vintage" in the title. If you swap "garage sale find" for "vintage" you will see a price more reflective of the value.., $2.50!


Sent from my bag phone...

 

[spike99250]

When Dewalt reintroduced itself to the market, their first saws were the same as the sawcats., You might be able to find one of those.
Those sawcats did hold up. The company I work for still has at least three still in use.
Most guys in the company hated those saws, myself included, but they took a beating.

 

[TOOLS4WORK]

is that a worm drive saw- i have a worm drive black and decker somewhere in my shop

 

[premierplayer]

T4W, it's a side winder
I gave mine to a friend for parts to recover his
I've been flying a Mikita since, a little lighter, and plenty tough

 

[sasquatch12]

Had a Super Saw cat, it was a great strong well built saw. Don't think they made them for too long.

 

[rbjenterprises]

I think that this is the same saw, just yellow not grey. I have a 20 year old one. Like a Timex, takes a lick and keeps on ticking.

http://www.lowes.com/ProductDisplay...gId=10051&cmRelshp=req&rel=nofollow&cId=PDIO1