1/4 drive torque

[_brian_]

A question for those who use impact drivers, the 1/4 kind. I have a Ryobi P238 which states the ability to produce 2000 inch pounds of torque, which approximates to 166 foot pounds. Now, I got to thinking that I cannot use a 1/4 drive ratchet at over 80-100 foot pounds as the anvil will break. So how can I use here a 1/4 drive at over 150 foot pounds? I suspect this has something to do with the ability to absorb the impacting force vs a constant force applied to the tool, but I hope someone with more solid knowledge can clarify.

Please avoid the ratings are not true and such things. For this question, let us please assume that the rating specified is correct as my question depends on those statements.

 

[Bondo]

Ayuh,..... It's the Impact factor,.......

Imagine tryin' to hold a 1/2" impact, in one hand, if it applied 600 lbs of torque into yer wrist,..??..??

It takes me a big ole breaker bar, 'n many feet of pipe to manually get to 600Ft.Lbs.....

 

[2ndGearRubber]

A question for those who use impact drivers, the 1/4 kind. I have a Ryobi P238 which states the ability to produce 2000 inch pounds of torque, which approximates to 166 foot pounds. Now, I got to thinking that I cannot use a 1/4 drive ratchet at over 80-100 foot pounds as the anvil will break. So how can I use here a 1/4 drive at over 150 foot pounds? I suspect this has something to do with the ability to absorb the impacting force vs a constant force applied to the tool, but I hope someone with more solid knowledge can clarify.

Please avoid the ratings are not true and such things. For this question, let us please assume that the rating specified is correct as my question depends on those statements.

Sorry, but that's the truth.

Remember that the torque on a ratchet is a constant turning force. Impacts don't have a constant twisting force, the force spikes as the hammers hit. I would imagine the peak theoretical number the impact can create is what is advertised. This is also likely based at the 1/4 hex shank, not the tip of the device being driven. Torque loss between the bit and tool is a factor.



My IR2235 is rated at 1350 ft/lbs of "nut busting" torque, whatever the hell that means. No, it cannot generate that under any circumstance.

 

[Rabid Badger]

A question for those who use impact drivers, the 1/4 kind. I have a Ryobi P238 which states the ability to produce 2000 inch pounds of torque, which approximates to 166 foot pounds. Now, I got to thinking that I cannot use a 1/4 drive ratchet at over 80-100 foot pounds as the anvil will break. So how can I use here a 1/4 drive at over 150 foot pounds? I suspect this has something to do with the ability to absorb the impacting force vs a constant force applied to the tool, but I hope someone with more solid knowledge can clarify.

You ever hit a wrench with a hammer to break a bolt loose? Same principle. An impact impacts the fastener to generate torque. The force is applied very briefly, which prevents stuff from breaking.

Please avoid the ratings are not true and such things. For this question, let us please assume that the rating specified is correct as my question depends on those statements.

Sorry man.

That 2000 in/lb rating is "breakaway" (aka BS) torque. I'd expect the real number to be around 1300. Man, TTI is getting awfully brazen with their nonsense torque ratings.

 

[cderalow]

Next time I swap tires I’ll toss my impact rated ⅜” hex adapter on my p236 and try to bust off some lug nuts.

I’d wager it’ll work.

(P236 is the precursor brushed version of the P238)


Sent from my iPhone using Tapatalk

 

[_brian_]

The reason I wanted to avoid the stated power debate is because my question is not about the driver itself or its power, it is about the concept. So while the stated is 2000 inch pounds (~166 foot pounds), even if the rating is 100 foot pounds, 100 foot pounds is enough to break the anvil on most 1/4 drive ratchets.