approach angle for garage

[Vintage Veloce]

Well, I thought I could make it flatter than this... but it looks like concrete leading to the garage might be inclined at 2" in 12" (9.5 degrees), and then the garage floor is level. Does that sound too steep? Am I going to have trouble with low cars?
C

 

[atch]

I lived with one like that for 13 years; and I live in the snowy part of the country. I never had any problems, even with my '48 Ford panel truck, which sits considerably lower than most any new car.

I do believe, though, that the top 5 feet or so transitioned from the 2/12 to level. I honestly don't remember as it's been 16 years since I lived there.

 

[honEXduner]

How long is the approach?

 

[VintageVeloce]

The approach, worst case, that is at that slope is 3 to 4 feet. So the rise is 6 to 8 inches in 3 or 4 feet.

Sent from my MotoG3 using Tapatalk

 

[larry_g]

Lets look at some math so you can decide.

Take a rig with a 120", (10') wheelbase.

so the rise in ten feet is 20"

So when you enter the garage worst case is 1/2 in and 1/2 out or each axle is 5' from the high point and the high point will be 10" above the plane across the bottom of the tires.

So 1/2 wb x 2" = clearance

wb is wheelbase in feet.

lg
no neat sig line

 

[Vintage Veloce]

lg,
That is great info, but I think you are discussing is "breakover angle" as opposed to "approach angle". Still useful very though, because if I make it past the approach, that is the next question.
C

 

[larry_g]

lg,
That is great info, but I think you are discussing is "breakover angle" as opposed to "approach angle". Still useful very though, because if I make it past the approach, that is the next question.
C

Sorry I went for worst case. For approach angle the math is similar. Instead of the 1/2 wb you use tire contact contact patch to furthest overhang point.

So if you have 3' of overhang then you'll need 6" of clearance. I'm not sure, without taxing my brain, if the same holds for departure angle.

lg
no neat sig line

 

[Vintage Veloce]

lg , for the breakover:

I think this should be:
clearance = 1/4 x (wheelbase in feet) x (rise in inches per foot)
I think it is 1/4 instead because there are wheels at both ends of the wheelbase.

Agree?
C

Lets look at some math so you can decide.

Take a rig with a 120", (10') wheelbase.

so the rise in ten feet is 20"

So when you enter the garage worst case is 1/2 in and 1/2 out or each axle is 5' from the high point and the high point will be 10" above the plane across the bottom of the tires.

So 1/2 wb x 2" = clearance

wb is wheelbase in feet.

lg
no neat sig line

 

[larry_g]

lg , for the breakover:

I think this should be:
clearance = 1/4 x (wheelbase in feet) x (rise in inches per foot)
I think it is 1/4 instead because there are wheels at both ends of the wheelbase.

Agree?
C

Well after drawing out a picture I do believe your correct. I failed to factor in that the wheels in the garage continue on a flat plane 10" above the original plane of the car, assuming the original plane was flat and parallel to the garage floor..

Another assumption is that the the rear wheels are on the apron incline when the car is 1/2 way in the building. If the rear wheels have not started to climb the incline/apron then the math gets harder and you will have to trig it out.

lg
no neat sig line

 

[Vintage Veloce]

My Sketch:

 

[larry_g]

My Sketch:

I concur. A mirror image of what I sketched out the second time.

lg
no neat sig line

 

[Vintage Veloce]

Thanks lg. I figured this out from your description. That was a big help.
C