we break concrete samples at work, when we break 6x12 we divide "load" by 28.27 when we break 4x8 we divide load by 12.45 to get psi. I want to read "load" on my hydraulic press, not psi, so ram size doesnt matter, because with load you can see failure, a 1/2 second before it happens. I just dont want to take my company break machine apart to see how the gauge is attach, too lazy and boss likes to yell
You would have had a much higher quality of results if you had said that you were testing concrete samples to start.
It sounds as the gauge on your press is already modified to be direct reading of force/load the press is outputting. It still is a PSI gauge, the face has just been replaced with the correction factor applied.
The concrete sample, depending on size, has to have a correction factor applied to get the PSI strength of the concrete. This correction factor is because a bigger sample will take more force to break but concrete PSI rating is pounds "per square inch" since the sample have the area of 28.27 square area for a 6" circle of the cylinder and 12.45 square inches for a 4" circle area of a cylinder that is the correction factor.
The PSI of the concrete is in no way related to the PSI inside the hydraulic cylinder, as hydraulics multiply force by using surface area of the piston. In many presses the piston/ram are one in the same as very few are two way cylinders. The only way the psi would matter directly is if the samples were exactly the same size as the piston in the cylinder of the press
In your press what you are calling the ram is the actually on the end of the cylinder rod.
*note* Multiple gauges could be installed and have the faces replaced the correction factor applied to be direct reading. One gauge would be for a 4" sample and another for a 6" sample.
There are some digital pressure gauges that can be programmed to displace force such as described a little bit down on this page.
https://www.apgsensors.com/about-us/blog/convert-psi-to-lbs-using-a-digital-pressure-gauge/
The few that I have seen with a quick google fu search that can do this cost in the $1000-1200 range. Again you would need one for each sample area size. The math wouldn't be quite the same as you would have to have the aforementioned correction factor for sample size as well.