matt_i
Well-known member
Some background, I am trying to finish adding a new shop to an existing shop. I have some reasonably high powered lighting (1kW) on the "old" side which often gets left on while I'm working in the "new" side. When I remember, and ultimately trying to conserve energy I have to walk all the way back thru to the single pole switch and turn it off.
It occurred to me to try to work smarter and not harder, and make this a 3 way circuit.
So I started making some circuit drawings to try to minimize the damage as the single pole switch for this circuit is set in drywall, with some access from above.
Drawing #1 is the original circuit, simple switch and a bulb to represent the lighting load.
Drawing #2 involves running a 14-3 "traveler" wire between the boxes, and then a 14-2 wire to carry the common-hot back to the bulb, so 2 wires would have to be run.
After thinking about the circuit for awhile, and trying to simplify, the redundancy is in the neutral wire which goes all the way over on the traveler 14-3 above and then comes back on the 14-2 above. If the neutral could just stay at the original box location, then the common-hot is the only one that has to come back. Essentially I could perform this function with a single 14-3 (enter Drawing #3). Functional problem solved, wire minimization = great.
But I have a new problem in that a 14-3 doesn't come in a black-red-orange. ..or any other 3rd color for as far as I know. Do I enter the extremely perilous territory of "phase-taping" a #14 awg, or do I just use Drawing #2, or is there something else easy that I'm missing. Thanks for your input.
Grounds eliminated for simplicity. They are there and present as normally used.
It occurred to me to try to work smarter and not harder, and make this a 3 way circuit.
So I started making some circuit drawings to try to minimize the damage as the single pole switch for this circuit is set in drywall, with some access from above.
Drawing #1 is the original circuit, simple switch and a bulb to represent the lighting load.
Drawing #2 involves running a 14-3 "traveler" wire between the boxes, and then a 14-2 wire to carry the common-hot back to the bulb, so 2 wires would have to be run.
After thinking about the circuit for awhile, and trying to simplify, the redundancy is in the neutral wire which goes all the way over on the traveler 14-3 above and then comes back on the 14-2 above. If the neutral could just stay at the original box location, then the common-hot is the only one that has to come back. Essentially I could perform this function with a single 14-3 (enter Drawing #3). Functional problem solved, wire minimization = great.
But I have a new problem in that a 14-3 doesn't come in a black-red-orange. ..or any other 3rd color for as far as I know. Do I enter the extremely perilous territory of "phase-taping" a #14 awg, or do I just use Drawing #2, or is there something else easy that I'm missing. Thanks for your input.
Grounds eliminated for simplicity. They are there and present as normally used.
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