To really evaluate the flow of the compressor at 90 psig, you would have to install a valve that you throttle back the flow out of the compressor (no regulator) to the point that the pressure remains constant with the compressor on and air flowing out. That way, your flow rate of air out of the comressor tank is the same as the air flow rate from the compressor. Then, you can measure the amount of time it takes to fill a certain volume. Using a light weight trash bag would be a good way. If you calc the volume of the filled trashbag and the amount of time it took to fill it, you will have CFM at atmospheric conditions. Capture the temperature and barometric pressure at that time.
Then, all you would need to do is use the following formula:
P1*V1 = P2*V2
Where:
P1 = barometric pressure converted to psia (not psig)
V1 = trash bag volumetric fill rate (cubic feet per minute)
T1 = Ambient temp
P2 = 104.7 psia (90 psig + 14.7psi (atmospheric pressure))
V2 = what you are solving for - the volumetric flow rate @ 90 psig in cubic feet per min
So it simplifies to:
P1*V1 / P2 = V2
There are alot of other factors involved here- compressor heat input resulting in air temp being different than ambient temp (difficult to measure adequately) innacuracies with your throttling valve setting, etc., but this should give you a good idea of the flowrate of air that you will actually be using for your tools.
I can give a much more detailed experiment and calculation, but the end result (answer) may only vary by 10% or so IMO.
Does that make any sense?