twistedpiston
Member
Hi everyone, I have been lurking for some time and gleaning tons of great info, I however find myself needing some help with something for which I just can't seem to find the answer. I'm sure someone here will have no problem figuring it out...
I need some help figuring the flat dimension for a 2 bend piece of aluminum. The final piece will be a simple “U” channel with 2 side legs measuring (outside dimensions) .56”, 90 degree bends with .171 radius and the middle part 1.92” The material is 2024 T3 .064
My calculations:
Setback = .235
Bend allowance = .369
.56 - .235 = .325
.56 - .235 = .325
1.92 – (2 x .235) = 1.45
.369 x 2 = .738
.325 + .325 + 1.45 + .738 = 2.838
My sight line is the BTL + 1 Radius
Can someone please verify / correct my calculations? When I bend the part, the .56 legs are long and the center flat is narrow. The sum of the differences in the short legs is close to the shortage in the center.
Thanks in advance. -Keith
I need some help figuring the flat dimension for a 2 bend piece of aluminum. The final piece will be a simple “U” channel with 2 side legs measuring (outside dimensions) .56”, 90 degree bends with .171 radius and the middle part 1.92” The material is 2024 T3 .064
My calculations:
Setback = .235
Bend allowance = .369
.56 - .235 = .325
.56 - .235 = .325
1.92 – (2 x .235) = 1.45
.369 x 2 = .738
.325 + .325 + 1.45 + .738 = 2.838
My sight line is the BTL + 1 Radius
Can someone please verify / correct my calculations? When I bend the part, the .56 legs are long and the center flat is narrow. The sum of the differences in the short legs is close to the shortage in the center.
Thanks in advance. -Keith

