2stroke1971
Active member
My read of the the diagram below is as follows: (for an old MIG welder)
From the bottom we see 3 lines out of the transformer. Two of them on the outer edges are AC voltage out of the transformer, and go to the rectifier. They join after the rectifier to become the (+) DC voltage for the welding wire.
The line in the middle coming out of the transformer....it comes from another tap in the transformer. It goes out to the feed motor, and also through what I guess is the inductor/coil. Coming out of that coil, it becomes the DC (-) for the ground clamp.
A MIG uses DC voltage. I would have expected the (-) for the ground clamp to have come out of the rectifier, and THEN through the inductor. The DC negative seems to come directly out of the transformer and then into the coil and then to the ground clamp. How then, is this DC?
In other words, take a simple rectifier, 2 ACs in, then a positive and negative DC out.
This rectifier seems to only have a (+) out. The DC negative bypasses the rectifier.
Any thoughts?
Thanks in advacne!
From the bottom we see 3 lines out of the transformer. Two of them on the outer edges are AC voltage out of the transformer, and go to the rectifier. They join after the rectifier to become the (+) DC voltage for the welding wire.
The line in the middle coming out of the transformer....it comes from another tap in the transformer. It goes out to the feed motor, and also through what I guess is the inductor/coil. Coming out of that coil, it becomes the DC (-) for the ground clamp.
A MIG uses DC voltage. I would have expected the (-) for the ground clamp to have come out of the rectifier, and THEN through the inductor. The DC negative seems to come directly out of the transformer and then into the coil and then to the ground clamp. How then, is this DC?
In other words, take a simple rectifier, 2 ACs in, then a positive and negative DC out.
This rectifier seems to only have a (+) out. The DC negative bypasses the rectifier.
Any thoughts?
Thanks in advacne!