Just bouncing an idea off the wall here...
So I have a big torque wrench (like this) for heavy truck wheels that I'd like to test the calibration of (indoors), through a digital torque adapter with a 4-point socket, and I've tried using a vise and 1-inch square steel bar to torque on, but the vise doesn't seem to clamp that tightly for up to 500 ft/lbs or so (right now I have it on a stand that isn't bolted down, so I've only gone up to 300 or less torque and the bar was starting to move out of position, then of course bolting the vise down to anything might not do, if I can't clamp it enough without pounding on it or breaking something).
Anyway, I was thinking of embedding the bar in a concrete cube instead (call it a torque block). Seems like it could work for really holding that bar in place, and I don't have anything to bolt it directly to otherwise (there don't seem to be brackets for that and what not, besides actual torque testing equipment that costs a fortune). How large do you think such a block would have to be (poured around a steel bar suspended in the middle, sticking out a few inches), so that it would hold under that kind of stress and not tip when torqued on? Or would you have other thoughts on this...
My guess would be 1x1 foot (about the size of a file cabinet drawer)... let's see I looked up the density of a cubic foot which says concrete would weigh about 133 lbs. Doubt I'd be moving that off the ground with a wrench (but then trucks are weighed in tonnage). Well I might have to try it (and maybe embed some square u-bolts for handles). Hmm, I also checked a torque calculator to get an idea of force on the object, which seems to say 500 ft/lbs from about a 45 inch wrench handle would generate something like 670 newtons or 150 pounds-force pushing down on the bar. So I gather pound-force and pound-mass are the same quantities on earth, and it's questionable if I'd tip it by exerting around 20 pounds more force on one side of a cube than it weighs (not sure, may need to make it heavier). Probably, yeah I did a rough estimation using two large sockets, putting a paint brush handle through the locking pin hole that's below center on the heavier one, then set a slightly lighter socket on top of the handle, and it tipped the heavier one. So I think the block would need to weigh more than the force being applied to a bar protruding from it (perhaps 18 inches/200lbs, considering that the handle in my little simulation was sticking out quite a bit more than the bar would, although the torque adapter adds an extra 10 inches, so maybe it was pretty close).
What else to consider? I also briefly looked up how torquing on steel might play out in concrete, and for example a 1-inch rebar anchor has a recommended torque for nut tension at 550 ft-lb (while its max load is in thousands of foot pounds, or over a hundred kilo newtons). So I suppose that's about the right size bar, although their embedment depth goes up as anchor diameter increases, being 16-inches for this one, while the 1/2 inch anchor has 7-inch embedment. I'm guessing my 12-inch bar may not need to be as deep, if their increased embedment is for load more so than tension (or toward an extremely high level of torque, since they're both measured as such).
A semi-educated guess then... or it'll be a sword in the stone.
So I have a big torque wrench (like this) for heavy truck wheels that I'd like to test the calibration of (indoors), through a digital torque adapter with a 4-point socket, and I've tried using a vise and 1-inch square steel bar to torque on, but the vise doesn't seem to clamp that tightly for up to 500 ft/lbs or so (right now I have it on a stand that isn't bolted down, so I've only gone up to 300 or less torque and the bar was starting to move out of position, then of course bolting the vise down to anything might not do, if I can't clamp it enough without pounding on it or breaking something).
Anyway, I was thinking of embedding the bar in a concrete cube instead (call it a torque block). Seems like it could work for really holding that bar in place, and I don't have anything to bolt it directly to otherwise (there don't seem to be brackets for that and what not, besides actual torque testing equipment that costs a fortune). How large do you think such a block would have to be (poured around a steel bar suspended in the middle, sticking out a few inches), so that it would hold under that kind of stress and not tip when torqued on? Or would you have other thoughts on this...
My guess would be 1x1 foot (about the size of a file cabinet drawer)... let's see I looked up the density of a cubic foot which says concrete would weigh about 133 lbs. Doubt I'd be moving that off the ground with a wrench (but then trucks are weighed in tonnage). Well I might have to try it (and maybe embed some square u-bolts for handles). Hmm, I also checked a torque calculator to get an idea of force on the object, which seems to say 500 ft/lbs from about a 45 inch wrench handle would generate something like 670 newtons or 150 pounds-force pushing down on the bar. So I gather pound-force and pound-mass are the same quantities on earth, and it's questionable if I'd tip it by exerting around 20 pounds more force on one side of a cube than it weighs (not sure, may need to make it heavier). Probably, yeah I did a rough estimation using two large sockets, putting a paint brush handle through the locking pin hole that's below center on the heavier one, then set a slightly lighter socket on top of the handle, and it tipped the heavier one. So I think the block would need to weigh more than the force being applied to a bar protruding from it (perhaps 18 inches/200lbs, considering that the handle in my little simulation was sticking out quite a bit more than the bar would, although the torque adapter adds an extra 10 inches, so maybe it was pretty close).
What else to consider? I also briefly looked up how torquing on steel might play out in concrete, and for example a 1-inch rebar anchor has a recommended torque for nut tension at 550 ft-lb (while its max load is in thousands of foot pounds, or over a hundred kilo newtons). So I suppose that's about the right size bar, although their embedment depth goes up as anchor diameter increases, being 16-inches for this one, while the 1/2 inch anchor has 7-inch embedment. I'm guessing my 12-inch bar may not need to be as deep, if their increased embedment is for load more so than tension (or toward an extremely high level of torque, since they're both measured as such).
A semi-educated guess then... or it'll be a sword in the stone.
Last edited: