kvom
Well-known member
When a wheel is mounted on a car or truck, is the vertical weight carried mainly by the clamping force on the wheel mount surface, or conversely by the studs themselves?
Hub-centric wheels which are generally OEM and more expensive aftermarket wheels have the center bore machined for the specific car. This allows the wheel's center bore to support most of the weight and force and then the lugs mainly secure the wheel on the hub.
Many aftermarket wheels, to reduce costs, have gone with an over-sized center bore and plastic or aluminum centering rings that are made to the spec of the car's hub. These hub designs still support some of the weight and the lugs again are used mainly to secure the wheel on the hub as well as support the weight.
Ultra cheap aftermarket wheels use an over-sized center bore and rely on the lug nuts or bolts to not only secure the wheel to the hub, but also support the weight as well.
The studs do not take a sheer force. If they do, they will fail quickly. Studs are NEVER meant to take sheer loads.
The studs are in tension, and that clamping force is what carries all sheer loads.
-mechanical engineer by trade
Agreed but hub piloted wheels do provide an extra layer of support.
The studs do not take a sheer force. If they do, they will fail quickly. Studs are NEVER meant to take sheer loads.
The studs are in tension, and that clamping force is what carries all sheer loads.
-mechanical engineer by trade
+1 an all points
Wheel studs are generally 4037 or 4140 and hardened to class 10.9. Most are M12 or M14 as well.
I don't know the shear strenght off hand. I'd have to calulate it at work...but its very high. In the tens of thousands of pounds. Then multiply that by the 5 wheel studs.
Even if the load was carried entirely in shear, (which its not), they would not quickly fail
ha!
I deleted my post after you quoted me.
I sounded too know-it-all-ish so I deleted it. But yeah, wheel studs could easily carry the shear load of a car. But the joint isn't entirely in shear like you said. The friction from the clamp load carries alot of the load as well. Probally the majority
it's 'shear', not sheer
and they do have a shear component, they have to, draw the force diagram...
the load is reduced by clamping/friction, and some designs a center bore hub lip...
it's also why the nut/lug bolts have a conical (ball or taper) surface that resesses into the wheel, to better distribute the forces over a larger area and divert/dilute its direction...
say the weight/wheel is 1000 lbs
the hub may carry most of that, if so equipped, clamping a large percentage, but some still rests on the lug...a 5/8' bolt has shear load capacity > 1000 lbs...but carries a fraction of that...and the load is spread over all the bolts, the %/bolt depending on the number...
They don't have to. You're talking about static loads of 1000 lbs. Think about the shear forces the studs "would" see under maximum braking, turning, etc.
No, the ball or taper is used for centering. And not all lug nuts/bolts use that design. As I mentioned previously, Toyotas don't.
http://img.photobucket.com/albums/v80/sakthao/Wheels and Tires/Lug Nuts/02-1.jpg
There's no taper between the wheel and lug nut in this case.
Think about the generic spacers that you can buy at AutoZone, Pepboys, etc. Like these.
http://customwheel.com/custom_wheels/images/wheelSpacers.jpg
The holes aren't matched to the studs/bolts, and they aren't hubcentric. That would mean that if the lugs/studs were really taking shear forces, that the wheel itself would "slip" with respect to the spacer. That doesn't happen, because all shear forces are taken away from the clamping friction between the hub and wheel.
I’m also an engineer, and get pretty riled up when people who should know better don’t.
Ugh...
Of course you break wheel studs if the studs are loose. If that's the case, you don't have clamping force. As soon as the studs see shear, you're overloading them, and they'll eventually break, likely sooner rather than later.
The car I race by the way hits over 1.5+G. Peaks of 1.6 laterally, and 1.1 longitudinally. Any RWD/AWD car with drag slicks on a drag strip is easily going 1+ G at launch.
Another example. http://students.ou.edu/K/Joseph.D.Kliewer-1/pics/Wheel.jpg
Single nut, knock off wheels used on race cars for quicker wheel/tire changes, less hardware/weight, etc.
Online article explaining it: http://images.google.com/imgres?img...en-US:official&um=1&ei=S6kFS6mKAY2SnAed_cTPCw
"The other type of joint is loaded by shear force (Fs). In a joint loaded in shear, the friction between the parts keep them from moving when subject to a shear force. The friction between the parts carries the load, not the fastener. An example of this type of joint would be a shock absorber mount or the driveshaft flange on an airhead. The greater the preload force, the greater the clamping force, the greater the friction, and the stronger the joint. With a properly designed and tightened joint, the bolt will not experience a direct shear load. "
I promise you on a properly torqued wheel, virtually all the torsional and radial loads on the wheel are transmitted through the face of the hub via friction...
