Interesting, but don't do it... academically, if they have the same resistance at all times, you'd get a 60 Amp breaker. Realistically, you can't depend on any more than the lower of the two. If you care why...
Each one is independently measuring the current passing through it. V=IR or I=V/R tells us that the current passing through the two parallel circuits depends on the resistance of the circuits. Assuming all the cable runs are equal and each breaker has the same resistance, the current will be divided equally between the two. That's a big assumption, though. Even slight differences in the resistance between the two circuits will cause more current to pass through one than the other, so you can't depend on this reliably unless they have specified resistance and the wiring is similarly controlled. I can promise that you'll never get more than 80 amps through that arrangement, and you'll never get less than 30.
If this is an AC circuit, you have a major reason not to do it (and this should be a NEC violation, but I can't cite chapter and verse off the top of my head)... The phase of each leg will be slightly different so instead of combining two identical sine waves, you'll get two sine waves of different phase, and the result will not be a sine wave. Run a motor, transformer, or any other inductive load off that and you can get overheating and buzzing.