To avoid these ads, REGISTER NOW!

Need to torque 750 lb ft counter clockwise

To avoid these ads, REGISTER NOW!

nelstomlinson

Well-known member
Joined
Jul 27, 2009
Messages
649
Location
Interior Alaska
750 foot pounds = 250 pounds on a three foot cheater, 125 pounds on a six foot cheater, 75 pounds on a 10 foot cheater, and so on. You can do it.
 

Ole Slewfoot

Well-known member
Joined
Feb 22, 2016
Messages
5,098
Location
Freedom, CA
Glad you worked it out OP.

There are some cheap 45-1 or so multipliers sold for truck lugs as cheap as $50. they come with a crank handle, but adapting to square isn
t that hard,



Here's my reasoning, I'm no expert, mechanical engineer, etc., just a thought, please correct me if I'm wrong.
If you took a large grade 8 bolt and nut (something that could take 750 ft. #s torque. Clamped in large vice.
Now use that 600# max wrench. Torque to 150#. Put wrench on noting exactly where it is, Ok...now torque to 300#. Say it moves 90 degrees or 12". Now go to 450#. Say it moves 60 degrees or 9". Now go to 600#. Say it moves 45 degrees or 6".
Now you have a mathematical pattern. Now you know how many degrees and inches you would have to go to get to 750#.
Where is my reasoning wrong? Wouldn't that work and be accurate?
Generally no, but if you have determined the yield strength of that particular fastener(assuming they are that consistent), then you can get close. Clamp force isn't linear, but in the right part of the curve, it is close.


So here is my puzzler with regard to handle extensions
extensions...

I want to torque bolt X to 1000 ft /lb.

I could hang 1000lb a foot down the wrench handle and do it if there was room.

I could go 10' out, and just hang 100 lb, but the frame is in the way.

So If I have a long enough handle can I run the wrench up 45*, and hang my 100lb weight such that it is horizontally 10' removed from the bolt(14' or so out the handle)?
 

Provincial

Well-known member
Joined
Sep 21, 2011
Messages
6,855
Location
Near Salem, OR
Glad you worked it out OP.

There are some cheap 45-1 or so multipliers sold for truck lugs as cheap as $50. they come with a crank handle, but adapting to square isn
t that hard,




Generally no, but if you have determined the yield strength of that particular fastener(assuming they are that consistent), then you can get close. Clamp force isn't linear, but in the right part of the curve, it is close.


So here is my puzzler with regard to handle extensions
extensions...

I want to torque bolt X to 1000 ft /lb.

I could hang 1000lb a foot down the wrench handle and do it if there was room.

I could go 10' out, and just hang 100 lb, but the frame is in the way.

So If I have a long enough handle can I run the wrench up 45*, and hang my 100lb weight such that it is horizontally 10' removed from the bolt(14' or so out the handle)?

Or apply the pull (weight) perpendicular to the handle. You could use a spring scale on the handle in order to measure the pull. In the case you describe, you would apply a pull perpendicular to the handle 10' from the center of the nut, and that pull force needs to show 100 lbs on the spring scale. In essence, this is a form of torque wrench.
 
To avoid these ads, REGISTER NOW!

MikeF2316

Well-known member
Joined
Dec 29, 2012
Messages
9,605
Location
Thornhill, ON
Glad you worked it out OP.

There are some cheap 45-1 or so multipliers sold for truck lugs as cheap as $50. they come with a crank handle, but adapting to square isn
t that hard,




Generally no, but if you have determined the yield strength of that particular fastener(assuming they are that consistent), then you can get close. Clamp force isn't linear, but in the right part of the curve, it is close.


So here is my puzzler with regard to handle extensions
extensions...

I want to torque bolt X to 1000 ft /lb.

I could hang 1000lb a foot down the wrench handle and do it if there was room.

I could go 10' out, and just hang 100 lb, but the frame is in the way.

So If I have a long enough handle can I run the wrench up 45*, and hang my 100lb weight such that it is horizontally 10' removed from the bolt(14' or so out the handle)?

The problem with this method is that the length of your torque arm is changing as the bolt turns, with your wrench angled up, the torque would be increasing as the wrench turns. This is assuming no friction, as the wrench falls the friction component would be going down too!

And I would bet that Sevenhills1952's method would get you so close it wouldn't matter. I doubt that it's getting near the yield point in this case. Break out the math, let's create a 4th order polynomial! :lol_hitti
 

rpcraft

Well-known member
Joined
Aug 14, 2014
Messages
1,057
Location
Waco
Glad you worked it out OP.

There are some cheap 45-1 or so multipliers sold for truck lugs as cheap as $50. they come with a crank handle, but adapting to square isn
t that hard,




Generally no, but if you have determined the yield strength of that particular fastener(assuming they are that consistent), then you can get close. Clamp force isn't linear, but in the right part of the curve, it is close.


So here is my puzzler with regard to handle extensions
extensions...

I want to torque bolt X to 1000 ft /lb.

I could hang 1000lb a foot down the wrench handle and do it if there was room.

I could go 10' out, and just hang 100 lb, but the frame is in the way.

So If I have a long enough handle can I run the wrench up 45*, and hang my 100lb weight such that it is horizontally 10' removed from the bolt(14' or so out the handle)?


Your in the realm of measuring ugga ugga's from your air tool there now, :lol_hitti
 

speed bump

Well-known member
Joined
May 28, 2008
Messages
6,317
Location
Butte Montana
At a previous employer we did a lot of things with a wrench of a known length and a scale pulled by a crane. In your case a 4 ft bar with a 250 lb spring scale would get you there for very little money.
 
To avoid these ads, REGISTER NOW!
Top Bottom