thanks for posting this.
Doesn't the new Williams USA wrench have an open end design like the Matco?
Skin, what were you using to get the extra leverage?
Nothing. Each wrenchs length was its own leverage.

The wrenches are metal and if you round a bolt it will spread permanently. The question is by how much.
even likely, that high quality wrenches are designed to keep deformation from rounding a bolt head within the elastic zone of the steel, meaning no plastic or permanent deformation.
Just because the wrenches are metal and deform during the process doesn't mean they will spread permanently.
Because there's variances in dimensional tolerances on fasteners (in this instance it's the distance across flats), can you use fasteners that are as close to being equal and of the same supplier?
The smaller the measurement across flats on the fastener, the more prone the wrench is going to round over the edge. If you can narrow the variances as much as possible between the fasteners we can really pin-point what the wrenches are capable of doing (the level of marring at the corners).
You mentioned that the wrenches that did roll over the corner were stretched beyond yield and the spread was measurable at the ends of the open-end. I just want to clarify that it was only at the ends, where spread is inevitably going to happen, correct?
Good crimany seriously? Pulling on those thin beam Snap-on wrenches must've hurt. I hope you had a glove on or a towel wrapped around it.![]()
Okay, lets agree to disagree then. They're hardened metal objects, they're being flexed, they will all spread permanently, the question is simply how much and how often is it being spread.
Sorry, but you are completely wrong!
Please keep an open mind, and learn from others trying to correct you. The joy of forums is that they are a wealth of knowledge.
Time to brush up on your basic Physics.
All metals are like an elastic spring (untill the yield point).
The strain ( i.e. extension) is directly proportional to to stress (i.e load).
Strain = Stress/ Young's Modulus.
The very basic principle all Engineering Design is based on.
A stronger/ harder material will have a higher Young's Modulus value.
This basically means that it will flex less for a given load, but a spring it remains.
But, once you said this
A stronger/ harder material will have a higher Young's Modulus value.
it's not necessarily true. Yes, steel has a higher E (young's modulus) than AL (by a factor of ~3). But steel, whether it's 1020, or 4140 at RC 40, has essentially the same E value.
you are somewhat correct in that the OP is wrong on this statement:
They're hardened metal objects, they're being flexed, they will all spread permanently, the question is simply how much and how often is it being spread
and you are correct when you said this:
All metals are like an elastic spring (untill the yield point).
But, once you said this
A stronger/ harder material will have a higher Young's Modulus value.
it's not necessarily true. Yes, steel has a higher E (young's modulus) than AL (by a factor of ~3). But steel, whether it's 1020, or 4140 at RC 40, has essentially the same E value.
Look it up on matweb.com before you argue and you'll see it's 29,000-30,000ksi for steel whether it's 1020 as-rolled or 4140 at RC 40, or whatever). Yes, the yield strength greatly varies, but both materials have the same E value and therefore WILL deform the same amount below the yield of the 1020. Of course the 1020 will reach yield sooner and permanently deform.